皮皮学，免费搜题
登录
搜题
【单选题】
Madonna and Michael Jackson are not considered heroes because ______.A.
they are not clear about the principles they should follow
B.
they are popular only among certain groups of people
C.
their primary concern is their own financial interests
D.
their performances do not improve their fans morally
拍照语音搜题，微信中搜索"皮皮学"使用
参考答案：
参考解析：
知识点：
皮皮学刷刷变学霸
举一反三
【简答题】若有定义int x,y;则下面程序段中不能实现以下函数关系的为()。 -1 (x<0)Y= 0 (x=0) 1 (x>0)A. if(x0)y=1;} Else y=0; C. if(x==0)if(x>0)y=1; else y=0; else y=-1; D. y=0if(x>=0) {if(x>0)y=1;} else y=-1;
【单选题】若有定义int x,y;则不能实现以下函数关系的程序段是( )。 y=1 (x>0) y=0 (x=0) y= - 1 (x<0)< /div>
A.
if(x<0) y=-1; else if(x==0) y=0; else y=-1;< /div>
B.
y=-1; if(x!=0) if(x>0) y=1; else y=0;
C.
y=0; if(x>=0) {if(x>0) y=1;} else y=-1;
D.
if(x>=0) if(x>0) y=1; else y=0; else y=-1;
【单选题】In Unit 6. By the end of story, ________________________.
A.
the writer was employed by the boss.
B.
the boss agreed to give the writer a try.
C.
the writer was refused by the boss.
D.
the boss asked the writer to wait for his call
【单选题】Which of the following is true about the end user of IT, according to an SOA philosophy?
A.
The end user should be thought of in the same way as an external customer.
B.
The end user's needs should be considered secondary to customers' needs.
C.
The end user's access to data should be limited to a specific geographic area due to security reasons.
D.
Multi-channel service delivery should be available exclusively to end users and not customers.
【单选题】若有定义int x,y;则下面程序段中不能实现以下函数关系的为( )。
A.
if(x<0)y=-1; else if(x= =0)y=0; else y=1;
B.
y=-1; if(x!=0) {if(x>0)y=1;} else y=0;
C.
if(x= =0) if(x>0)y=1; else y=0 else y=1;
D.
y=0; if(x>=0); {if(x>0)y=1;} else y=-1;
【单选题】若有定义int x,y;则下面程序段中不能实现以下函数关系的为( )。 (x0)时,Y=1;
A.
if(x<0)y=-1; Else if(x==0) y=0; Else y=1;< /div>
B.
y=-1; if(x!=0){if(x>0)y=1;} Else y=0;
C.
if(x==0)if(x>0)y=1; else y=0; else y=-1;
D.
y=0if(x>=0) {if(x>0)y=1;} else y=-1;
【单选题】若有定义int x,y;则下面程序段中不能实现以下函数关系的为()。 -1 (x0)
A.
if(x<0)y=-1; Else if(x==0) y=0; Else y=1;
B.
y=-1; if(x!=0){if(x>0)y=1;} Else y=0;
C.
if(x==0)if(x>0)y=1; else y=0; else y=-1;
D.
y=0if(x>=0) {if(x>0)y=1;} else y=-1;
【简答题】将矿块(粒)分离为不同组分比重的方法有 、 、 、 。
相关题目：
【单选题】若有定义int x,y;则不能实现以下函数关系的程序段是( )。 y=1 (x>0) y=0 (x=0) y= - 1 (x<0)< /div>
A.
if(x<0) y=-1; else if(x==0) y=0; else y=-1;< /div>
B.
y=-1; if(x!=0) if(x>0) y=1; else y=0;
C.
y=0; if(x>=0) {if(x>0) y=1;} else y=-1;
D.
if(x>=0) if(x>0) y=1; else y=0; else y=-1;
【单选题】若有定义int x,y;则下面程序段中不能实现以下函数关系的为( )。 (x0)时,Y=1;
A.
if(x<0)y=-1; Else if(x==0) y=0; Else y=1;< /div>
B.
y=-1; if(x!=0){if(x>0)y=1;} Else y=0;
C.
if(x==0)if(x>0)y=1; else y=0; else y=-1;
D.
y=0if(x>=0) {if(x>0)y=1;} else y=-1;