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【单选题】
船舶航行在通航分道制水域端部附近特别谨慎的驾驶· 其原因是: Ⅰ、在此区域会遇时直航船解除保速的义务Ⅱ、 端部附近船舶可能进行较大幅度的转向Ⅲ、 航线与通航分道交叉的船舶为避免穿越通航分道,可能在此区域转向通过
A.
B.
Ⅰ、Ⅱ
C.
Ⅱ、Ⅲ
D.
Ⅰ、Ⅱ、Ⅲ
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【简答题】(本小题满分14分) 设 是定义在 上的函数,用分点 将区间 任意划分成 个小区间,如果存在一个常数 ,使得和式 ( )恒成立,则称 为 上的有界变差函数. (1)函数 在 上是否为有界变差函数?请说明理由; (2)设函数 是 上的单调递减函数,证明: 为 上的有界变差函数; (3)若定义在 上的函数 满足:存在常数 ,使得对于任意的 、 时, .证明: 为 上的有界变差函数.
【单选题】中机型船的特点是:1、空载吃水差较小;2、重载吃水差较大;3、货舱舱容浪费较大
A.
①、②
B.
②、③
C.
①、③
D.
①、②、③
【单选题】From the last paragraph, we can learn that multitaskers usually________.
A.
drive very skillfully
B.
go in for different tasks
C.
fail to react quickly to potential dangers
D.
refuse to explain the reasons for their behavior
【单选题】From the passage we can learn that .
A.
society has been influenced by science fiction more in direct ways
B.
communications and transportation are usually impacted indirectly by science fiction
C.
science fiction has no direct negative influence upon society
D.
science fiction has influenced society both in technological and cultural areas
【简答题】设f(x)是定义在[a,b]上的函数,用分点T:a=x 0 <x 1 <…<x i﹣1 <x i <…x n =b 将区间[a,b]任意划分成n个小区间, 如果存在一个常数M>0,使得 和 ≤M(i=1,2,…,n)恒成立, 则称f(x)为[a,b]上的有界变差函数. (1)函数f(x)=x 2 在[0,1]上是否为有界变差函数?请说明理由; (2)设函数f(x)是[a,b]上的单调递减函数,证明...
【判断题】Usually we can learn from shipping marks the destination and weight of the goods in transit.
A.
正确
B.
错误
【单选题】We can learn from the text that
A.
public visitors intended to reap great profits in the fair.
B.
some countries initially hesitated to support the project.
C.
technological progress usually precedes an economic boom.
D.
sponsoring corporations once dismissed the technology.
【单选题】We can learn from Paragraph 3 that deep venous thrombosis usually happens because _____.
A.
the economy class is not spacious enough
B.
there are too many economy-class passengers
C.
passengers are not allowed to walk during the flight
D.
the low pressure in the cabin prevents blood flowing smoothly
【多选题】中机型船的特点是:
A.
空载吃水差较小
B.
重载吃水差较大
C.
货舱舱容浪费较大
【单选题】中机型船的特点是( )I.空载吃水差较小;II.重载吃水差较大;III.货舱舱容浪费较大
A.
I.II
B.
II.III
C.
I.III
D.
I.II.III
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