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【单选题】
谁最一我
A.
é∷7ん
B.
んλЯé
C.
é∷λ7
D.
ЯRλ7
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【简答题】设有一组关键字{9,01,23,14,55,20,84,27},采用哈希函数:H(key)=key mod 7 ,表长为10,用开放地址法的线性探测再散列方法Hi=(H(key)+di) mod 10(di=1,2,3,...,)解决冲突。要求:对该关键字序列构造哈希表,并计算查找成功的平均查找长度。
【单选题】Until today we have reached a stage ______ we have almost no rights at all..
A.
why
B.
what
C.
how
D.
where
【简答题】设有一组关键字 {9,01,23,14,55,20,84,27} ,采用哈希函数: H ( key ) =key mod 7 ,表长为 10 ,用开放地址法的二次探测再散列方法 Hi=(H(key)+di) mod 10(di=1 2 ,2 2 ,3 2 ,...,) 解决冲突。要求:对该关键字序列构造哈希表,并计算查找成功的平均查找长度。
【单选题】We have show today. [     ]
A.
a
B.
an
C.
is
【单选题】We don't have ______ English lesson today. We have ______ Chinese lesson. [     ]
A.
an; an
B.
an; a
C.
a; a
D.
a; an
【简答题】We have at times in the past been enemies.We have great differences today。What bring us together is that we have common interests which transcend those differences.
【简答题】设有一组关键字{9,1,23,14,55,20,80,27},采用哈希函数:H____=key%7 ,表长为10,用开放地址法的二次探测再散列方法Hi=____+di)%10____解决冲突。要求:对该关键字序列构造哈希表,并计算查找成功的平均查找长度。
【判断题】555 定时器可以构成多谐振荡器、单稳态触发器、施密特触发器
A.
正确
B.
错误
【单选题】.Not until today ___ a stage___ we have enough right to deal with everything
A.
we have reached; where
B.
have we reached; what
C.
have we reached; where
D.
we have reached; that
【简答题】设有一组关键字( 9 , 1 , 23 , 14 , 55 , 20 , 84 , 27 ),采用哈希函数: H ( key ) =key %7 ,表长为 10 ,用开放地址法的二次探测法处理冲突。要求:对该关键字序列构造哈希表,并计算查找成功的平均查找长度。
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