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【简答题】
Read the sentences. Type in the number of the correct definition for the bold word. condition n. 1 [U] the state of s.t. (good, bad, weak, strong): The condition of his health is excellent. || The condition of that machinery is bad. 2 [C] a disease, medical problem: My grandmother has a heart condition. 3 [C] a requirement: Our book contract has two special conditions in it; we must pay $10,000 in advance, and we must renew the contract annually. 4 [C] external factors: My living conditions were terrible at my old apartment building; I had no running water or heat for two months. 5 on the condition that: provided that: Yes, we will renew the contract next year on the condition that we make money on the deal. - v. [T] 6 to shape the attitudes or behavior of: We conditioned our children to not watch TV during the week. Several people in my family have heart conditions .
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【单选题】— Have we ________water? — Yes, ________. We'd better get some. [     ]
A.
given out; we have run it out
B.
run out of, our water has run out
C.
used up; our water has been run out
D.
run out; our water has run out
【单选题】下列哪种氨基酸属于亚氨基酸
A.
丝氨酸
B.
脯氨酸
C.
亮氨酸
D.
组氨酸
【简答题】质量为25kg的小孩坐在秋千板上,小孩重心离系绳子的横梁2.5m,如果秋千板摆到最低点时,小孩运动速度大小是5m/s,他对秋千板的压力是多少(g取10m/s)
【多选题】中学物理强调科学探究,而猜想与假设是科学探究中的重要环节。下列关于猜想与假设具备的教育功能的说法正确的是______。
A.
猜想与假设能培养学生的发散性思维
B.
假设能培养学生的收敛性思维
C.
学生在猜想与假设中,不断地在发散性思维和收敛性思维之间转换,促进了学生创造性思维的发展
D.
猜想与假设在整个探究活动中起到一种引导性作用,是探究活动的主线
E.
科学探究的结论是围绕着猜想与假设进行的
【简答题】写出以下程序段的输出结果(________) char *p="abcdefgh",*r; long *q; q=(long *)p; q++; r=(char *) q; printf("%s\n",r);
【单选题】下列应作为企业收入核算的是
A.
商场销售商品代收增值税
B.
咨询公司取得的咨询服务收入
C.
罚款收入
D.
固定资产清理净收益
【单选题】下列哪些说法是正确的() (1)冗余压缩法不会减少信息量,可以原样恢复原始数据。 (2)冗余压缩法减少了冗余,不能原样恢复原始数据。 (3)冗余压缩法是有损压缩法。 (4)冗余压缩的压缩比一般都比较小。
A.
(1)(3)
B.
(4)
C.
(1)(3)(4)
D.
仅(3)
【单选题】如图所示,质量为25kg的小孩坐在秋千板上,小孩的重心离系绳子的栋梁2.5m。如果秋千板摆到最低点时,小孩运动速度的大小是5m/s,此时小孩将手中离地高为0.8m的小球自由释放。一切阻力均不计,则下列说法正确的是
A.
秋千摆摆到最低点时对小孩的支持力约为250N
B.
秋千摆摆到最低点时对小孩的支持力约为500N
C.
小球离开手后到落地时运动的水平位移为0
D.
小球离开手后到落地时运动的水平位移约为3m
【单选题】下列哪种氨基酸属于亚氨基酸
A.
甘氨酸
B.
脯氨酸
C.
丝氨酸
D.
组氨酸
【简答题】请写出以下程序段的输出结果:def foo(): print("starting...") while True: res = yield 4 print("res:",res)g = foo()print(next(g))print("*"*20)print(next(g))
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