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【单选题】
患者男性,59岁,工人。1年前无明显诱因出现双腕、双手关节和双膝、踝、足、跖趾关节肿痛,伴晨僵,时间约12分钟,疼痛以夜间明显,影响行动。实验室检查:血沉55mm/h,RF(+)。关节X线检查:双手骨质疏松,腕部关节间隙变窄。使用青霉胺治疗,护士不用观察哪些不良反应
A.
关节肿胀
B.
有无皮疹、蛋白尿、血尿
C.
头痛
D.
白细胞减少
E.
肾功能异常
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【简答题】已知复数z 1 =3+4i，z 2 的平方根是2+3i，且函数 f(x)= 2x x+1 ． （1）求 f( . z 1 + z 2 ) ； （2）若f（z）=1+i，求z．
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【单选题】What devices are used to enter information into the system?
A.
RAMs
B.
Projections
C.
Output devices
D.
Input devices
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【多选题】Rhetorical devices fall into three classifications, namely _________________, _________________, ___________________.
A.
phonetic devices
B.
lexical devices
C.
syntactic devices
D.
grammatical devices
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【单选题】Consider the following configuration：   /devices/diskP1 is a member of disk group grp1.        /devices/diskP2 is a member of disk group grp1.        /devices/diskP3 is a member of disk group grp1.   ...
A.
ALTER DISKGROUP grp1  ADD DISK ’/devices/diskP1’，  ADD DISK ’/devices/diskP4’；
B.
ALTER DISKGROUP grp1  ADD DISK ’/devices/disk*4’；
C.
ALTER DISKGROUP grp1  ADD DISK ’/devices/diskP*’；
D.
ALTER DISKGROUP grp1  ADD DISK ’/devices/diskQ*’，  ADD DISK ’/devices/diskP*’；
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【简答题】如果f(z)=u+iv是z的解析函数，证明
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【简答题】求k值，使u=x 2 +ky 2 为调和函数，再求u的共轭调和函数v．使解析函数f(z)=u+iv满足f(i)=-1
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【简答题】已知函数，f（x）=x 3 -ax 2 -9x+11且f′（1）=-12． （I）求函数f（x）的解析式； （II）求函数f（x）的极值．
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【单选题】Consider the following command to add a new disk group called "tdgroupA" with two failover groups： CREATE DISKGROUP tdgroupA NORMAL REDUNDANCY FAILOVERGROUP control01 DISK ’/devices/A1’，  ’/devices/A2...
A.
This command would result in an error because a disk group can have only one failover group.
B.
This command would result in an error because the /devices/A1 disk is a member of another disk group tdgroup1.
C.
A new disk group called tdgroupA will be added with two failover groups and the /devices/A1 disk will get reattached to the new disk group without being detached from the existing one.
D.
A new disk group called tdgroupA will be added with two failover groups and the /devices/A1 disk will be ignored for the new disk group because it is a member of an existing disk group tdgroup1.
E.
A new disk group called tdgroupA will be added with two failover groups and the /devices/A1 disk gets detached from the existing disk group tdgroup1 and attached to the new disk group tdgroupA
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【单选题】You have configured the ASM instance for the PROD database of iPod Corporation. You have specified the following parameter values in the initialization parameter file：   DB_CREATE_FILE_DEST=’devices/g...
A.
Both the members will be stored in the ’devices/grp1/P’ directory.
B.
Both the members will be stored in the ’devices/d_grp2/Q’ directory.
C.
Both the members will be stored in the ’devices/d_grp3/R’ directory.
D.
One member will be stored in the ’devices/d_grp2/Q’ directory and the other in the ’devices/d_grp3/R’ directory.
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【简答题】已知复数z 1 =3+4i，z 2 的平方根是2+3i，且函数 f(x)= 2x x+1 ． （1）求 f( . z 1 + z 2 ) ； （2）若f（z）=1+i，求z．
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【简答题】求由下列条件确定解析函数f(z)=u+iv (1)u=x 2 +xy-y 2 ，f(i)=-1+i； (2)v=e x (ycosy+xsiny),f(0)=0
查看完整题目与答案
【单选题】What devices are used to enter information into the system?
A.
RAMs
B.
Projections
C.
Output devices
D.
Input devices
查看完整题目与答案
【多选题】Rhetorical devices fall into three classifications, namely _________________, _________________, ___________________.
A.
phonetic devices
B.
lexical devices
C.
syntactic devices
D.
grammatical devices
查看完整题目与答案
【单选题】Consider the following configuration：   /devices/diskP1 is a member of disk group grp1.        /devices/diskP2 is a member of disk group grp1.        /devices/diskP3 is a member of disk group grp1.   ...
A.
ALTER DISKGROUP grp1  ADD DISK ’/devices/diskP1’，  ADD DISK ’/devices/diskP4’；
B.
ALTER DISKGROUP grp1  ADD DISK ’/devices/disk*4’；
C.
ALTER DISKGROUP grp1  ADD DISK ’/devices/diskP*’；
D.
ALTER DISKGROUP grp1  ADD DISK ’/devices/diskQ*’，  ADD DISK ’/devices/diskP*’；
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【简答题】如果f(z)=u+iv是z的解析函数，证明
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【简答题】求k值，使u=x 2 +ky 2 为调和函数，再求u的共轭调和函数v．使解析函数f(z)=u+iv满足f(i)=-1
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【简答题】已知函数，f（x）=x 3 -ax 2 -9x+11且f′（1）=-12． （I）求函数f（x）的解析式； （II）求函数f（x）的极值．
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【单选题】Consider the following command to add a new disk group called "tdgroupA" with two failover groups： CREATE DISKGROUP tdgroupA NORMAL REDUNDANCY FAILOVERGROUP control01 DISK ’/devices/A1’，  ’/devices/A2...
A.
This command would result in an error because a disk group can have only one failover group.
B.
This command would result in an error because the /devices/A1 disk is a member of another disk group tdgroup1.
C.
A new disk group called tdgroupA will be added with two failover groups and the /devices/A1 disk will get reattached to the new disk group without being detached from the existing one.
D.
A new disk group called tdgroupA will be added with two failover groups and the /devices/A1 disk will be ignored for the new disk group because it is a member of an existing disk group tdgroup1.
E.
A new disk group called tdgroupA will be added with two failover groups and the /devices/A1 disk gets detached from the existing disk group tdgroup1 and attached to the new disk group tdgroupA
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【单选题】You have configured the ASM instance for the PROD database of iPod Corporation. You have specified the following parameter values in the initialization parameter file：   DB_CREATE_FILE_DEST=’devices/g...
A.
Both the members will be stored in the ’devices/grp1/P’ directory.
B.
Both the members will be stored in the ’devices/d_grp2/Q’ directory.
C.
Both the members will be stored in the ’devices/d_grp3/R’ directory.
D.
One member will be stored in the ’devices/d_grp2/Q’ directory and the other in the ’devices/d_grp3/R’ directory.
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